Therefore, when the value is checked on line 40, the condition of the statement is true. Remember that an index in an array begins with 0. This solution is also fairly common. Do you need similar project to be completed? I have a java assignment that I really need help with. So, we can use this condition for our sum calculation.
The value of sum will be used as reference for further calculations is the program. This also fits the common. So here, we will use a 2-dimensional array as the container representing the matrix. The first diagonal is made up of the numbers that lie on an imaginary line that goes across the square from top left to bottom right. If possible place the next number at that position.
One thing do is reformat your code so that it's properly aligned and indented. This is also problematic because the rest of the code will raise an exception in this case, instead of simply returning false. Please use code tags when posting code:. Start filling the square from top left hand corner. Consequently, the statements from lines 41-49 will be executed. For more information about what that means,.
Here is the 5x5 square that you get if you follow this method: 11 18 25 2 9 10 12 19 21 3 4 6 13 20 22 23 5 7 14 16 17 24 1 8 15 Write a program whose input is the number n and whose output is the magic square of order n if n is odd. Any move will be wrapped around like pac man or train tunnel in Matrix. The value of magic was originally set to true, and once we found a sum calculation that is not the same as the reference value, we set its value to false. The first calculation will be used as a reference, so the results of of the rest will be compared with it. I do not have any vb editor but following code executes well in cscript program available in windows. Then, when i becomes 1, the inner loop will start again with j equals to 0.
This means that this line is not to be processed or executed. Implementation of Magic Square Palindromes in Java import java. Since you only use it once, I wouldn't bother with the sum variable. At the end of the nested loop, the contents of the square array is illustrated as below: On lines 25 and 26, the sum of the numbers in the first row is calculated. And here's the code that does it. Then, lines 31 and 32 are executed, where the inner loop will cycle 3 times.
Lines 53-61 contain statements to calculate the sum of numbers on this diagonal. So just choosing one row and one column wouldn't be an adequate , would it? A magic square is one where the sum of each row, column, and diagonal is the same. The detailed calculations occur inside all those methods being called from here. Let this position be i,j. Next, we need to check the sum of numbers in each diagonal. Notice that the sum of row index and column index of each of these cells are the same, which is 2? · The sum of each row, each column and the two diagonals add up to the identical value.
Calculating lastColumn first ensures that we don't do extra calculations on each iteration of the loop. Ten years ago, a mathematician called Yasusi Kanada wrote the original java code. This is a symbol used to tell the compiler to ignore the rest of the line. I now generate squares for all values of n, instead of just the simple case where n is odd. As mentioned earlier, we also use i as reference to the row index, and j for the column index. Making n final ensures that people won't expect it to change.
But i keep getting false when i run the program? Obviously, lines 64-73 contain statements that calculate the sum of numbers on the second diagonal. Optionally, show the magic number. In the next block of statements lines 17-22 , each cell of the square array is accessed and its content is displayed, using the same method. If they are, we can say that it is a magic square. For example, in the first outer cycle when j is 0 , the sum of all numbers in the first column is calculated.
If not possible, follow these steps. Assumtion is that reader has understading of the Siamese method. We use i and j as the reference to the row index and column index respectively. The columns The rest of code correctly tests whether rows and both diagonals have the same sum, but it doesn't consider columns. But are you sure that's what you want to do? Write a method that accepts a two-dimensional array as an argument, and determines whether the array is a Lo Shu Magic Square. That would be greatly appreciated.